Neo4j

andrej_zivec · 02-24-2022

Hi, When I run the querry like MATCH (a) RETURN a the result (all node properties) is in one column/string. I know that I can write RETURN a.prop1, a.prop2,.... to have properties in each column. But I look for a universal solution like if I do not k...

andrej_zivec · 01-07-2022

I have, let's say a graph with 50 nodes. With Cypher I find 3 possible paths from node A to node B (the result of the Cypher query is also a graph .. a sub-graph) MATCH p=((a:label {Pro1:'A'})-[*7]->(b:label {Pro1:'B'})) RETURN p On the path from A t...

andrej_zivec · 03-06-2022

Sorry but this is not the case for me .... I need columns. Anyway thank you for your answer it is also useful I learned something new

andrej_zivec · 01-11-2022

Thank you for the detailed explanation. First I have to try your solution in other examples to completely understand it and then do the next step . It will be much easier if there will be a native Neo4j function (maybe exists but I don't know for it...

andrej_zivec · 01-10-2022

Thank you very much ... I am new to Cypher and my logic is still on tables, maybe because of this I see the query as a sub-graph but as I understand this is a list of paths. You write "because your match results in a list of paths and you want to pro...

andrej_zivec · 01-09-2022

Thank you @filantrop and @glilienfield for the answers but maybe I was no so clear what I want .... Here is an example of the graph: CREATE (n9:label {Name: "Pro1"})-[:FRIEND]->(:label {Name: "Pro2"})-[:FRIEND]->(:label { Name: "Pro3"})-[:FRIEND]->(n...

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How to count relationships of nodes in subgraph

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