Convert Graph to a Tree

[jeet]

I have this graph

it has intermediate nodes of yellow colors

I want convert this to a tree in way that it clones Engine node and its children as 2 diff engine nodes one under Train and one under car as it has 2 incoming links

is something like this possible?

Thanks

[ameyasoft]

If I understood correctly, you can try this:

Get the id of your Engine node. I recreated your scenario and in my case id = 13.

MATCH (a) where id(a) = 13  
CALL apoc.path.spanningTree(a,{maxLevel:2}) YIELD path
return path

Result:

[jeet]

ameyasoft:

Thanks @ameyasoft however I was looking to have 2 diff engine nodes one under car and one under train.

[ameyasoft]

Your data model shows one Engine node is connected to both Train and Car nodes. If you need two separate Engines then you should have:

(Train-[]- (Engine {type: "train"}) 
(Car)-[]-(Engine {type: "car"})

[jeet]

I was able to find apoc.convert.toTree() this solves my issue i get 2 copies of engines

MATCH p=(n:Part {partNumber:"100", revision: "A"})-[:HAS_BOM_PROPERTY|WITH_PART*]->(m) WITH COLLECT(p) AS ps CALL apoc.convert.toTree(ps) yield value RETURN value;

however i need to get rid the intermediate yellow nodes now.

https://run.mocky.io/v3/75583fed-56f5-4c0e-b378-a768ce53b015

[tony_chiboucas]

jeet:

however i need to get rid the intermediate yellow nodes now.

MATCH (p1:Part)-[r1]->(b:BOM)-[r2]->(p2:Part)
MERGE (p1)-[rBom:BOM]->(p2)
SET rBom = b
DETACH DELETE b