Convert 8 July 2013 to 7/8/2013

[ameyasoft]

I need to convert date 8 July 2013 to 7/8/2013 format. Any solution?

[stefan_armbrust]

use apoc.date.parse/format.

[andrew_bowman · Accepted solution]

More specifically the APOC function call would be:

return apoc.date.parse('8 July 2013', 'ms', 'dd MMMM yyyy')

[ameyasoft]

Thanks Stefan and Andrew for the suggestions. This worked for me:

return apoc.date.format(apoc.date.parse('8 July 2013', 'ms', 'dd MMMM yyyy'), 'ms', 'MM/dd/yyyy')

Result: 07/08/2013